Wednesday, April 12, 2017

options - Deriving Delta Hedge error in the B-S setup (part 2)


In this paper paper page 16-19 by Davis and this discussion derivation of the hedging error in a black scholes setup, the derivation of the delta hedging error in the Black Scholes model is discussed.


The result is strong and interesting but when I try go through the proof I don't quite understand several steps of it. He is using Ito a couple of times but doesn't really explain how and his definitions of processes could benefit from short explanations.


Can anyone in here provide a more thorough proof?



Answer



The paper could be clearer indeed.


It is a slightly confusing topic, but the important step here is to understand the consequence of the derivative $C$ in the portfolio being priced at the assumed vol $\sigma$. This implies (by Black-Scholes) that it will by definition be true that:


$\theta_t + \frac{\partial{C}}{\partial{S}}rS_t+ \frac{1}{2}\frac{\partial^2{C}}{\partial{S^2}}\sigma^2S_t^2 = rC_t$ (Eq. 1)



That is, the theta of $C$ is linked to the known quantities $\sigma, S, r$ and to the two Greeks delta and gamma. (This is of course the starting point of the Black-Scholes formula).


Now, it is also true that $C_t$ dynamics in your portfolio must (by Ito) depend on the true dynamics of $S_t$ and in particular we have:


$dC_t = \theta_tdt+ \frac{\partial{C}}{\partial{S}}dS_t+ \frac{1}{2}\frac{\partial^2{C}}{\partial{S^2}}dS_t^2$ (Eq. 2)


This is where the important bit happens: you can replace $\theta_t$ in Eq. 2 by its value derived from Eq. 1. What have we got ?


$dC_t = rC_tdt + \frac{\partial{C}}{\partial{S}}(dS_t-rS_tdt)+ \frac{1}{2}\frac{\partial^2{C}}{\partial{S^2}}(dS_t^2-\sigma^2S^2dt)$ (Eq. 3)


And of course if $S_t$ follows a GBM with volatility $\beta$, the third term turns out as:


$ \frac{1}{2}\frac{\partial^2{C}}{\partial{S^2}}(\beta^2-\sigma^2)S^2dt$


This is where the hedging error comes from in a delta-hedged portfolio.


You should work this out starting with $\Pi_t = C_t - \Delta_t S_t$ to play with the mechanics for yourself but a crucial point to note is that all derivatives (theta, delta, gamma) in Eq. 1 and in Eq. 2 depend on the assumed (or pricing or implied) vol $\sigma$.


This is the reason why you can replace $\theta_t$ in Eq. 2. Once the call is in your portfolio, it must be valued at some $\sigma$, and this (and not $\beta$) determines its theta for hedging purposes. $\theta_t \equiv \theta_t(\sigma)$.



This is also why the hedging error is a function of your valuation gamma. $\frac{\partial^2{C}}{\partial{S^2}} \equiv \frac{\partial^2{C}}{\partial{S^2}}(\sigma)$


(Note they are not just a function of $\sigma$ but hopefully the point is clear).


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