Monday, March 18, 2019

portfolio management - Diversification, Rebalancing and Different Means


I have found many financial authors making generalizations about GM and AM but they are wrong in certain circumstances. Could someone explain their reasoning?


My fact why they are wrong is based Jensen inequality:


$\sum^{n}_{i=1} p_{i} f(x_{i}) \geq f( \sum_{i=1}^{n} p_{i} x_{i})$


for concave up functions, verified here. Now the special case is:


$\sqrt[n]{x_{1}x_{2}...x_{n}} \leq \frac{x_{1}+x_{2}+...+x_{n}}{n}$


For concave down functions, the corresponding result can be obtained by reversing the inequality, more here.


Author 1




Rebalancing and diversification go hand in hand. There is no diversification benefit without rebalancing – otherwise the total return will simply be the weighted average of the long-term geometric returns. If you don’t rebalance to asset types, you will get no diversification benefit. If you can’t rebalance to an asset type, you cannot get diversification benefits.
Rebalancing benefits increase as volatility rises, and decreases in less volatile times. The benefit of rebalancing after a 10% movement is more than 10 times the benefit after a 1% movement, and the benefit from rebalancing after a 50% move is more than 5 times the benefit after a 10% move. The greatest benefit comes in times, like 2008-2009, when there are wild movements in portfolios. -- diversification does not assure profit or protect against loss in a declining that affects numerous asset types. Source.



Suppose we have a concave-down environment so


$\sqrt[n]{x_{1}x_{2}...x_{n}} \geq \frac{x_{1}+x_{2}+...+x_{n}}{n}$.



  1. Now following the logic in the paragraph the total return is simply the weighted average of the long-term geometric returs. We know from the latter result that it is greater than or equal to the arithmetic mean. Is there a diversification benefit with rebalancing?

  2. Then the numbers thrown in the next bolded sentence are a bit odd. Why would there be such a benefit if we just noticed that it is not necessarily so if our environment is concave-down environment (valuations going down)?

  3. But the last sentence saves this writer! No error here.



Author 2.


William Bernstein here goes one step further, ignoring the Jensen:



The effective (geometric mean) return of a periodically rebalanced portfolio always exceeds the weighted sum of the component geometric means.



The implicit premise behind such statements probably is that the market in the long-run is rising, very well right to some extent. But with that assumption, the problem of asset allocation simplifies to the Jensen -- an even with such premise, it should be noticed to the reader (or such sentences are wrong).


Author 3.


Many works rely on the ambiguous assertions such as Ilmanen's Expected Return -book, page 485:



the arithmetic mean of a series is always higher than the geometric mean (AM > GM) except when there is a zero volatility (AM = GM). A simple Taylor series expansion show a good approximate is $GM \approx AM - \frac{Variance}{2}.$




...but the bolded sentence is wrong. You can make a function with concave values and $AM < GM$.


Questions



  1. What are the authors meaning here?

  2. Are they wrong or do they have some some hidden premises that I am missing?

  3. Why are they stating such issues about AM and GM as they cannot always be true?




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