The recent regulation (page 32) on PRIIPs requires to compute a VaR-equivalent volatility defined as
VEV=√3.842−2lnVaR−1.96√T
Does anyone have an idea how they came up with that formula?
Answer
Let's assume T=1 and let S be a geometric gaussian process with zero drift, i.e. ln(S1/S0) is normally distributed with mean −1/2×VEV2 and volatility VEV.
Then
ln(VaR/S0)=−1/2VEV2−VEV×1.96 with the VAR at 0.975 quantile.
This is a quadratic equation in VEV, with solutions
VEV=−1.96±√1.962−2ln(VaR/S0).
We take the positive solution and are done.
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