Thursday, August 29, 2019

Black--Scholes hedging argument


I'm trying to understand the standard hedging argument to derive the Black--Scholes PDE. There's one aspect of the derivation which I can't get passed and I'd be very grateful for some clarification here.


We make the standard assumptions: underlying follows a geometric BM, i.e. dSt=μStdt+σStdWt and we let V(St,t) be an option written on this security so that by Ito's Lemma, we have:


dVt=(Vt+μStVS+12σ2S2t2VS2)dt+(σStVS)dWt


All good so far. We then set-up a portfolio consisting of a single option and some amount Δ(St,t) of the underlying whose value is given by Πt=Vt+Δ(St,t)St. It is then assumed that this portfolio be self-financing, i.e. that there are no additional inflows or outflows of cash, formalised as dΠt=dVt+Δ(St,t)dSt. We then choose Δ(St,t)=VS and then by substituting this into the above formula and using self-financing, we quickly obtain a riskless portfolio and the Black--Scholes PDE follows from there.



The point that confuses me is that it is not clear to me that we can definitely construct a portfolio satisfying Πt=VtVSSt which also must satisfy dΠt=dVtVSdSt. Every text I can find simply assumes that you can and proceeds as above. However, the existence of such a portfolio implies that VSSt=t0VS(Su,u)dSu and I don't see that this is necessarily true, that is to say, I don't see how such a portfolio can exist? What am I missing?


The interesting thing is that I have followed a different derivation of Black--Scholes where the portfolio instead consists of some amount of the underlying and some amount of a risk-free instrument Bt, i.e. Πt=α(St,t)St+β(St,t)Bt. Here we choose α(St,t)=VS as before to remove the risk but this time the freedom in β(St,t) seems to mean that we can ensure the portfolio is self-financing and therefore I am happy with this version of the argument.


I would really like to understand both arguments and where it is that I am going wrong in the first so any help is gratefully appreciated!




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